x^2+3x+99=2

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Solution for x^2+3x+99=2 equation:


Simplifying
x2 + 3x + 99 = 2

Reorder the terms:
99 + 3x + x2 = 2

Solving
99 + 3x + x2 = 2

Solving for variable 'x'.

Reorder the terms:
99 + -2 + 3x + x2 = 2 + -2

Combine like terms: 99 + -2 = 97
97 + 3x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
97 + 3x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-97' to each side of the equation.
97 + 3x + -97 + x2 = 0 + -97

Reorder the terms:
97 + -97 + 3x + x2 = 0 + -97

Combine like terms: 97 + -97 = 0
0 + 3x + x2 = 0 + -97
3x + x2 = 0 + -97

Combine like terms: 0 + -97 = -97
3x + x2 = -97

The x term is 3x.  Take half its coefficient (1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
3x + 2.25 + x2 = -97 + 2.25

Reorder the terms:
2.25 + 3x + x2 = -97 + 2.25

Combine like terms: -97 + 2.25 = -94.75
2.25 + 3x + x2 = -94.75

Factor a perfect square on the left side:
(x + 1.5)(x + 1.5) = -94.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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